Are the following statements 'True' or 'False'? Justify your answers.
If the graph of a polynomial intersects the $x$-axis at exactly two points,it need not be a quadratic polynomial.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The statement is 'True'.
If the graph of a polynomial intersects the $x$-axis at exactly two points,it does not necessarily have to be a quadratic polynomial.
$A$ polynomial of degree $n > 2$ can also intersect the $x$-axis at exactly two points if it has two real roots and the remaining $(n-2)$ roots are imaginary (non-real complex roots).
For example,a polynomial of degree $4$ can have two real roots and two imaginary roots,resulting in a graph that crosses the $x$-axis at only two points.

Explore More

Similar Questions

From the given figure,find the number of zeros of $y=p(x)$.

For each of the following,find a quadratic polynomial whose sum and product of the zeroes are as given respectively. Also,find the zeroes of these polynomials by factorisation.
Sum of zeroes $= -\frac{8}{3}$,Product of zeroes $= \frac{4}{3}$

Answer the following and justify:
If on division of a polynomial $p(x)$ by a polynomial $g(x)$,the quotient is zero,what is the relation between the degrees of $p(x)$ and $g(x)$?

The graph of $p(x) = -x^2 + x + 6$ is a.........

State the degree of the given polynomial: $p(x) = x^{2} - \sqrt{3}x^{3} + 4x^{7} + 9$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo